indefinite-integration

Question: $\int_{{}}^{{}}{\frac{x{{e}^{x}}}{{{(1+x)}^{2}}}dx=}$

1) $\frac{{{e}^{-x}}}{1+x}+c$

2) $-\frac{{{e}^{-x}}}{1+x}+c$

3) $\frac{{{e}^{x}}}{1+x}+c$

4) $-\frac{{{e}^{x}}}{1+x}+c$

Solution:

Explanation: No Explanation

Integration by parts

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