indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{{{\cos }^{-1}}x.\sqrt{1-{{x}^{2}}}}dx=}$

1) $\log ({{\cos }^{-1}}x)+c$

2) $-\log ({{\cos }^{-1}}x)+c$

3) $-\frac{1}{2{{({{\cos }^{-1}}x)}^{2}}}+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by substitution

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