indefinite-integration

Question: If $\int_{{}}^{{}}{{{e}^{x}}\sin x\ dx=\frac{1}{2}{{e}^{x}}\ .\ a+c}$, then $a=$



1) $\sin x-\cos x$
2) $\cos x-\sin x$
3) $-\cos x-\sin x$
4) $\cos x+\sin x$
Solution: Explanation: No Explanation
Integration by parts

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