indefinite-integration

Question: $\int_{{}}^{{}}{{{x}^{2}}\sin 2x}\ dx=$

1) $\frac{1}{2}{{x}^{2}}\cos 2x+\frac{1}{2}x\sin 2x+\frac{1}{4}\cos 2x+c$

2) $-\frac{1}{2}{{x}^{2}}\cos 2x+\frac{1}{2}x\sin 2x+\frac{1}{4}\cos 2x+c$

3) $\frac{1}{2}{{x}^{2}}\cos 2x-\frac{1}{2}x\sin 2x+\frac{1}{4}\cos 2x+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by parts

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