indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{({{\tan }^{-1}}x)}^{3}}}{1+{{x}^{2}}}\,dx=}$

1) ${{({{\tan }^{-1}}x)}^{4}}+c$

2) $\frac{{{({{\tan }^{-1}}x)}^{4}}}{4}+c$

3) $2{{\tan }^{-1}}x+c$

4) $2{{({{\tan }^{-1}}x)}^{2}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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