indefinite-integration

Question: $\int{\text{cose}{{\text{c}}^{4}}x\,dx}=$

1) $\cot x+\frac{{{\cot }^{3}}x}{3}+c$

2) $\tan x+\frac{{{\tan }^{3}}x}{3}+c$

3) $-\cot x-\frac{{{\cot }^{3}}x}{3}+c$

4) $-\tan x-\frac{{{\tan }^{3}}x}{3}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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