indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}\ dx}$ equals

1) $\log ({{e}^{x}}-{{e}^{-x}})+c$

2) $\log ({{e}^{x}}+{{e}^{-x}})+c$

3) $\log ({{e}^{-x}}-{{e}^{x}})+c$

4) $\log (1-{{e}^{-x}})+c$

Solution:

Explanation: No Explanation

Integration by substitution

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