indefinite-integration

Question: $\int_{{}}^{{}}{x\cos {{x}^{2}}\ dx}$ is equal to

1) $-\frac{1}{2}{{\sin }^{2}}x+c$

2) $\frac{1}{2}{{\sin }^{2}}x+c$

3) $-\frac{1}{2}\sin {{x}^{2}}+c$

4) $\frac{1}{2}\sin {{x}^{2}}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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