indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{{{\cos }^{2}}x{{(1-\tan x)}^{2}}}dx=}$



1) $\frac{1}{\tan x-1}+c$
2) $\frac{1}{1-\tan x}+c$
3) $-\frac{1}{3}\frac{1}{{{(1-\tan x)}^{3}}}+c$
4) None of these
Solution: Explanation: No Explanation
Integration by substitution

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