indefinite-integration

Question: $\int_{{}}^{{}}{\frac{x+1}{\sqrt{1+{{x}^{2}}}}dx}=$

1) $\sqrt{1+{{x}^{2}}}+{{\tan }^{-1}}x+c$

2) $\sqrt{1+{{x}^{2}}}-\log \{x+\sqrt{1+{{x}^{2}}}\}+c$

3) $\sqrt{1+{{x}^{2}}}+\log \{x+\sqrt{1+{{x}^{2}}}\}+c$

4) $\sqrt{1+{{x}^{2}}}+\log (\sec x+\tan x)+c$

Solution:

Explanation: No Explanation

Integration by substitution

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