indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{x\sqrt{{{x}^{2}}-1}}\ dx=}$

1) ${{\cos }^{-1}}x+c$

2) ${{\sec }^{-1}}x+c$

3) ${{\cot }^{-1}}x+c$

4) ${{\tan }^{-1}}x+c$

Solution:

Explanation: No Explanation

Fundamental integration

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