differentiation

Question: If the normal to the curve ${{y}^{2}}=5x-1$ , at the point (1, –2) is of the form $ax-5y+b=0$ , then a and b are



1) 4, – 14
2) 4, 14
3) –4, 14
4) –4, –14
Solution: Explanation: No Explanation
Tangent and Normal

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