differentiation

Question: If $z=\frac{y}{x}\left[ \sin \frac{x}{y}+\cos \left( 1+\frac{y}{x} \right) \right]$, then $x\frac{\partial z}{\partial x}=$



1) $y\frac{\partial z}{\partial y}$
2) $-y\frac{\partial z}{\partial y}$
3) $2y\frac{\partial z}{\partial y}$
4) $2y\frac{\partial z}{\partial x}$
Solution: Explanation: No Explanation
Partial differentiation

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