differentiation

Question: If $z=\sec \,(y-ax)+\tan (y+ax),$ then $\frac{{{\partial }^{2}}z}{\partial {{x}^{2}}}-{{a}^{2}}\frac{{{\partial }^{2}}z}{\partial {{y}^{2}}}=$



1) z
2) 2z
3) 0
4) –z
Solution: Explanation: No Explanation
Partial differentiation

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