differentiation

Question: If ${{u}^{2}}={{(x-a)}^{2}}+{{(y-b)}^{2}}+{{(z-c)}^{2}}$, then $\sum \frac{{{\partial }^{2}}u}{\partial {{x}^{2}}}=$

1) $\frac{2}{u}$

2) $\frac{3}{u}$

3) 0

4) $\frac{1}{u}$

Solution:

Explanation: No Explanation

Partial differentiation

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