differentiation

Question: If $u={{\tan }^{-1}}\left( \frac{{{x}^{3}}+{{y}^{3}}}{x-y} \right)$, then $x\frac{\partial u}{\partial x}+y\frac{\partial u}{\partial y}=$

1) $\sin 2u$

2) $\cos 2u$

3) $\tan 2u$

4) $\sec 2u$

Solution:

Explanation: No Explanation

Partial differentiation

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