Categories > differentiation > Differentiation by substitution > If $y=\sin px$ and ${{y}_{n}}$ is the $n^{th}$ derivative of $y$, then $\begin{vmatrix} y&{{y_1}}&{{y_2}}\\ {{y_3}}&{{y_4}}&{{y_5}}\\ {{y_6}}&{{y_7}}&{{y_8}} \end{vmatrix}$ is equal to

differentiation

Question: If $y=\sin px$ and ${{y}_{n}}$ is the $n^{th}$ derivative of $y$, then $\begin{vmatrix} y&{{y_1}}&{{y_2}}\\ {{y_3}}&{{y_4}}&{{y_5}}\\ {{y_6}}&{{y_7}}&{{y_8}} \end{vmatrix}$ is equal to


1) 1
2) 0
3) – 1
4) None of these
Solution: Explanation: No Explanation
Differentiation by substitution Higher order derivatives

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