Categories > differentiation > Differentiation by substitution > If $y=1-x+\frac{{{x}^{2}}}{2!}-\frac{{{x}^{3}}}{3!}+\frac{{{x}^{4}}}{4!}-$....., then $\frac{{{d}^{2}}y}{d{{x}^{2}}}=$

differentiation

Question: If $y=1-x+\frac{{{x}^{2}}}{2!}-\frac{{{x}^{3}}}{3!}+\frac{{{x}^{4}}}{4!}-$....., then $\frac{{{d}^{2}}y}{d{{x}^{2}}}=$


1) $x$
2) $-x$
3) $-y$
4) $y$
Solution: Explanation: No Explanation
Differentiation by substitution Higher order derivatives

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