differentiation

Question: The differential coefficient of ${{\tan }^{-1}}\sqrt{x}$ with respect to $\sqrt{x}$ is



1) $\frac{1}{\sqrt{1+x}}$
2) $\frac{1}{2x\sqrt{1+x}}$
3) $\frac{1}{2\sqrt{x(1+x)}}$
4) $\frac{1}{1+x}$
Solution: Explanation: No Explanation
Differentiation by substitution Higher order derivatives

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