differentiation

Question: Differential coefficient of $\frac{{{\tan }^{-1}}x}{1+{{\tan }^{-1}}x}$ w.r.t. ${{\tan }^{-1}}x$ is

1) $\frac{1}{1+{{\tan }^{-1}}x}$

2) $\frac{-1}{1+{{\tan }^{-1}}x}$

3) $\frac{1}{{{(1+{{\tan }^{-1}}x)}^{^{2}}}}$

4) $\frac{-1}{2\,{{(1+{{\tan }^{-1}}x)}^{2}}}$

Solution:

Explanation: No Explanation

Differentiation by substitution Higher order derivatives

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