differentiation

Question: If $y={{\tan }^{-1}}\left( \frac{x}{\sqrt{1-{{x}^{2}}}} \right)$, then $\frac{dy}{dx}=$

1) $-\frac{1}{\sqrt{1-{{x}^{2}}}}$

2) $\frac{x}{\sqrt{1-{{x}^{2}}}}$

3) $\frac{1}{\sqrt{1-{{x}^{2}}}}$

4) $\frac{\sqrt{1-{{x}^{2}}}}{x}$

Solution:

Explanation: No Explanation

Differentiation by substitution Higher order derivatives

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