Categories > 3-d > Line and plane > The equation of the plane through the point $(2,-1,-3)$and parallel to the lines $\frac{x-1}{3}=\frac{y+2}{2}=\frac{z}{-4}$ and $\frac{x}{2}=\frac{y-1}{-3}=\frac{z-2}{2}$ is

3-d

Question: The equation of the plane through the point $(2,-1,-3)$and parallel to the lines $\frac{x-1}{3}=\frac{y+2}{2}=\frac{z}{-4}$ and $\frac{x}{2}=\frac{y-1}{-3}=\frac{z-2}{2}$ is


1) $8x+14y+13z+37=0$
2) $8x-14y+13z+37=0$
3) $8x+14y-13z+37=0$
4) $8x+14y+13z-37=0$
Solution: Explanation: No Explanation
Line and plane

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)

Previous Question Next Question

Related Questions