3-d

Question: The point of intersection of the line $\frac{x-1}{3}=\frac{y+2}{4}=\frac{z-3}{-2}$ and plane $2x-y+3z-1=0$ is



1) $(10,\,\,-10,\,3)$
2) $(10,\,\,10,\,-3)$
3) $(-10,\,\,10,\,3)$
4) None of these
Solution: Explanation: No Explanation
Line and plane

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