3-d

Question: The equation of the perpendicular from the point $(\alpha ,\beta ,\gamma )$ to the plane $ax+by+cz+d=0$ is

1) $a(x-\alpha )+b(y-\beta )+c(z-\gamma )=0$

2) $\frac{x-\alpha }{a}=\frac{y-\beta }{b}=\frac{z-\gamma }{c}$

3) $a(x-\alpha )+b(y-\beta )+c(z-\gamma )=abc$

4) None of these

Solution:

Explanation: No Explanation

Plane

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