3-d

Question: A plane meets the co-ordinate axes in $A,B,C$ and $(\alpha ,\beta ,\gamma )$ is the centered of the triangle $ABC$ . Then the equation of the plane is



1) $\frac{x}{\alpha }+\frac{y}{\beta }+\frac{z}{\gamma }=3$
2) $\frac{x}{\alpha }+\frac{y}{\beta }+\frac{z}{\gamma }=1$
3) $\frac{3x}{\alpha }+\frac{3y}{\beta }+\frac{3z}{\gamma }=1$
4) $\alpha x+\beta y+\gamma z=1$
Solution: Explanation: No Explanation
Plane

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