3-d

Question: The distance between the planes $x+2y+3z+7=0$ and $2x+4y+6z+7=0$ is



1) $\frac{\sqrt{7}}{2\sqrt{2}}$
2) $\frac{7}{2}$
3) $\frac{\sqrt{7}}{2}$
4) $\frac{7}{2\sqrt{2}}$
Solution: Explanation: No Explanation
Plane

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