3-d

Question: If a plane cuts off intercepts $OA=a,OB=b,$ $OC=c$ from the co-ordinate axes, then the area of the triangle $ABC$ =

1) $\frac{1}{2}\sqrt{{{b}^{2}}{{c}^{2}}+{{c}^{2}}{{a}^{2}}+{{a}^{2}}{{b}^{2}}}$

2) $\frac{1}{2}(bc+ca+ab)$

3) $\frac{1}{2}abc$

4) $\frac{1}{2}\sqrt{{{(b-c)}^{2}}+{{(c-a)}^{2}}+{{(a-b)}^{2}}}$

Solution:

Explanation: No Explanation

Plane

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