3-d

Question: The direction cosines of the line $\frac{3x+1}{-3}=\frac{3y+2}{6}=\frac{z}{-1}$ are

1) $\left( \frac{1}{3},\frac{2}{3},\,0 \right)$

2) $\left( -1,\frac{2}{3},\,1 \right)$

3) $\left( -\frac{1}{2},\,\text{ }1,\,-\frac{1}{2} \right)$

4) $\left( -\frac{1}{\sqrt{6}},\frac{2}{\sqrt{6}},-\frac{1}{\sqrt{6}} \right)$

Solution:

Explanation: No Explanation

System of co-ordinates Direction cosines and direction ratios Projection

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