3-d

Question: The shortest distance between the lines $\frac{x-3}{3}=\frac{y-8}{-1}=\frac{z-3}{1}$ and $\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}$ is



1) $\sqrt{30}$
2) $2\sqrt{30}$
3) $5\sqrt{30}$
4) $3\sqrt{30}$
Solution: Explanation: No Explanation
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