vectors-m

Related Questions

• A unit vector perpendicular to the plane determined by the points $P\,(1,\,\,-1,\,\,2),\,\,Q\,(2,\,\,0,\,-1)$ and $R\,(0,\,\,2,\,\,1)$ is

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• The points with position vectors $10\,\mathbf{i}+3\,\mathbf{j},\,\,12\,\mathbf{i}-5\,\mathbf{j}$ and $a\,\mathbf{i}+11\,\mathbf{j}$ are collinear, if $a=$

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• If in the given figure $\overrightarrow{OA}=\mathbf{a},\,\,\,\overrightarrow{OB}=\mathbf{b}$ and $AP\,\,:\,\,PB=m\,\,:\,\,n,$ then $\overrightarrow{OP}=$

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• If three points A, B, C are collinear, whose position vectors are $\mathbf{i}-2\mathbf{j}-8\mathbf{k},\,\,5\mathbf{i}-2\mathbf{k}$ and $11\,\mathbf{i}+\,3\,\mathbf{j}+7\mathbf{k}$ respectively, then the ratio in which B divides AC is

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• If $\overrightarrow{{{F}_{1}}}=\mathbf{i}-\mathbf{j}+\mathbf{k},$ $\overrightarrow{{{F}_{2}}}=-\mathbf{i}+2\mathbf{j}-\mathbf{k},$ $\overrightarrow{{{F}_{3}}}=\mathbf{j}-\mathbf{k},$ $\vec{A}=4\mathbf{i}-3\mathbf{j}-2\mathbf{k}$ and $\vec{B}=6\mathbf{i}+\mathbf{j}-3\mathbf{k},$ then the scalar product of $\overrightarrow{{{F}_{1}}}+\overrightarrow{{{F}_{2}}}+\overrightarrow{{{F}_{3}}}$and $\overrightarrow{AB}$ will be

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