vectors-m

Related Questions

• For any two vectors a and b, ${{(\mathbf{a}\times \mathbf{b})}^{2}}$ is equal to

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• If a, b, c are non-collinear vectors such that for some scalars x, y, z, $x\mathbf{a}+y\mathbf{b}+z\mathbf{c}=\mathbf{0},$ then

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• $\mathbf{a},\,\mathbf{b}$ and c are three vectors with magnitude $|\mathbf{a}|\,=4,$ $|\mathbf{b}|\,=4,$ $|\mathbf{c}|\,=2$ and such that $\mathbf{a}$ is perpendicular to $(\mathbf{b}+\mathbf{c}),\,\mathbf{b}$ is perpendicular to $(\mathbf{c}+\mathbf{a})$ and $\mathbf{c}$ is perpendicular to $(\mathbf{a}+\mathbf{b}).$ It follows that $|\mathbf{a}+\mathbf{b}+\mathbf{c}|$ is equal to

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• Three forces $\mathbf{i}+2\,\mathbf{j}-3\,\mathbf{k},\,\,2\,\mathbf{i}+3\,\mathbf{j}+4\,\mathbf{k}$ and $\mathbf{i}-\mathbf{j}+\mathbf{k}$ are acting on a particle at the point (0, 1, 2). The magnitude of the moment of the forces about the point $(1,\,-2,\,0)$ is

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• If $\vec{\lambda }$ is a unit vector perpendicular to plane of vector a and b and angle between them is $\theta$, then a . b will be

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