vectors-m

Question: If $A\,(-1,\,\,2,\,\,3),\,\,B\,(1,\,\,1,\,\,1)$ and $C\,(2,\,\,-1,\,\,3)$ are points on a plane. A unit normal vector to the plane ABC is

1) $\pm \,\left( \frac{2\mathbf{i}+2\mathbf{j}+\mathbf{k}}{3} \right)$

2) $\pm \,\left( \frac{2\mathbf{i}-2\mathbf{j}+\mathbf{k}}{3} \right)$

3) $\pm \,\left( \frac{2\mathbf{i}-2\mathbf{j}-\mathbf{k}}{3} \right)$

4) $-\,\left( \frac{2\mathbf{i}+2\mathbf{j}+\mathbf{k}}{3} \right)$

Solution:

Explanation: No Explanation

Vector Product Cross Product of two vectors

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