vectors-m

Question: The unit vector perpendicular to the vectors $6\mathbf{i}+2\mathbf{j}+3\mathbf{k}$ and $3\mathbf{i}-6\mathbf{j}-2\mathbf{k},$ is



1) $\frac{2\mathbf{i}-3\mathbf{j}+6\mathbf{k}}{7}$
2) $\frac{2\mathbf{i}-3\mathbf{j}-6\mathbf{k}}{7}$
3) $\frac{2\mathbf{i}+3\mathbf{j}-6\mathbf{k}}{7}$
4) $\frac{2\mathbf{i}+3\mathbf{j}+6\mathbf{k}}{7}$
Solution: Explanation: No Explanation
Vector Product Cross Product of two vectors

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