vectors-m

Question: A unit vector perpendicular to the plane determined by the points (1, – 1, 2), (2, 0, – 1) and (0, 2, 1) is

1) $\pm \,\frac{1}{\sqrt{6}}\,(2\mathbf{i}+\mathbf{j}+\mathbf{k})$

2) $\frac{1}{\sqrt{6}}\,(\mathbf{i}+2\mathbf{j}+\mathbf{k})$

3) $\frac{1}{\sqrt{6}}\,(\mathbf{i}+\mathbf{j}+\mathbf{k})$

4) $\frac{1}{\sqrt{6}}\,(2\mathbf{i}-\mathbf{j}-\mathbf{k})$

Solution:

Explanation: No Explanation

Vector Product Cross Product of two vectors

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