vectors-m

Question: If the diagonals of a parallelogram are represented by the vectors $3\mathbf{i}+\mathbf{j}-2\mathbf{k}$ and $\mathbf{i}+3\mathbf{j}-4\mathbf{k},$ then its area in square unit is



1) $5\sqrt{3}$
2) $6\sqrt{3}$
3) $\sqrt{26}$
4) $\sqrt{42}$
Solution: Explanation: No Explanation
Vector Product Cross Product of two vectors

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