vectors-m

Related Questions

• If $\overrightarrow{{{F}_{1}}}=\mathbf{i}-\mathbf{j}+\mathbf{k},$ $\overrightarrow{{{F}_{2}}}=-\mathbf{i}+2\mathbf{j}-\mathbf{k},$ $\overrightarrow{{{F}_{3}}}=\mathbf{j}-\mathbf{k},$ $\vec{A}=4\mathbf{i}-3\mathbf{j}-2\mathbf{k}$ and $\vec{B}=6\mathbf{i}+\mathbf{j}-3\mathbf{k},$ then the scalar product of $\overrightarrow{{{F}_{1}}}+\overrightarrow{{{F}_{2}}}+\overrightarrow{{{F}_{3}}}$and $\overrightarrow{AB}$ will be

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• $\mathbf{a}$ and $\mathbf{b}$ are two non-collinear vectors, then $x\mathbf{a}+y\mathbf{b}$ (where x and y are scalars) represents a vector which is

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• If G and G' be the centroids of the triangles ABC and $A'B'C'$ respectively, then $\overrightarrow{AA}'+\overrightarrow{BB'}+\overrightarrow{CC}'=$

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• $(\mathbf{a}\,.\,\mathbf{i})\,\mathbf{i}+(\mathbf{a}\,.\,\mathbf{j})\mathbf{j}+(\mathbf{a}\,.\,\mathbf{k})\,\mathbf{k}=$

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• ABCDE is a pentagon. Forces $\overrightarrow{AB},\,\overrightarrow{AE},\,\overrightarrow{DC},\,\overrightarrow{ED}$ act at a point. Which force should be added to this system to make the resultant ${{\cos }^{-1}}\frac{4}{5}$

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