conic-section

Question: The equation to the hyperbola having its eccentricity 2 and the distance between its foci is 8



1) $\frac{{{x}^{2}}}{12}-\frac{{{y}^{2}}}{4}=1$
2) $\frac{{{x}^{2}}}{4}-\frac{{{y}^{2}}}{12}=1$
3) $\frac{{{x}^{2}}}{8}-\frac{{{y}^{2}}}{2}=1$
4) $\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1$
Solution: Explanation: No Explanation
Hyperbola

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