conic-section

Question: The eccentricity of the hyperbola $\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{25}=1$ is



1) 3/4
2) 3/5
3) $\sqrt{41}/4$
4) $\sqrt{41/5}$
Solution: Explanation: No Explanation
Hyperbola

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