The equation of the hyperbola whose foci are the foci of the ellipse $\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{9}=1$ and the eccentricity is 2, is

Question

Accepted Answer

$\frac{{{x}^{2}}}{4}-\frac{{{y}^{2}}}{12}=1$

Answer

$\frac{{{x}^{2}}}{4}+\frac{{{y}^{2}}}{12}=1$

Answer

$\frac{{{x}^{2}}}{12}+\frac{{{y}^{2}}}{4}=1$

Answer

$\frac{{{x}^{2}}}{12}-\frac{{{y}^{2}}}{4}=1$

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