conic-section

Question: The equation of a hyperbola, whose foci are (5, 0) and (–5, 0) and the length of whose conjugate axis is 8, is

1) $9{{x}^{2}}-16{{y}^{2}}=144$

2) $16{{x}^{2}}-9{{y}^{2}}=144$

3) $9{{x}^{2}}+16{{y}^{2}}=144$

4) $16{{x}^{2}}-9{{y}^{2}}=12$

Solution:

Explanation: No Explanation

Hyperbola

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