conic-section

Question: The equation of the normal to the hyperbola $\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1$ at $(-4,\ 0)$ is



1) $y=0$
2) $y=x$
3) $x=0$
4) $x=-y$
Solution: Explanation: No Explanation
Hyperbola

Rate this question:

Average rating: (0 votes)

Previous Question Next Question