conic-section

Question: The value of m, for which the line $y=mx+\frac{25\sqrt{3}}{3}$, is a normal to the conic $\frac{{{x}^{2}}}{16}-\frac{{{y}^{2}}}{9}=1$, is

1) $\sqrt{3}$

2) $-\frac{2}{\sqrt{3}}$

3) $-\frac{\sqrt{3}}{2}$

4) 1

Solution:

Explanation: No Explanation

Hyperbola

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