conic-section

Question: The latus rectum of the hyperbola $9{{x}^{2}}-16{{y}^{2}}+72x-32y-16=0$ is



1) $\frac{9}{2}$
2) $-\frac{9}{2}$
3) $\frac{32}{3}$
4) $-\frac{32}{3}$
Solution: Explanation: No Explanation
Hyperbola

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