The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its foci is at (18, 0). The equation of the hyperbola is

Question

Accepted Answer

$\frac{{{(x-5)}^{2}}}{25}-\frac{{{y}^{2}}}{144}=1$

Answer

$\frac{{{x}^{2}}}{25}-\frac{{{y}^{2}}}{144}=1$

Answer

$\frac{{{x}^{2}}}{25}-\frac{{{(y-5)}^{2}}}{144}=1$

Answer

$\frac{{{(x-5)}^{2}}}{25}-\frac{{{(y-5)}^{2}}}{144}=1$

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