The locus of the point of intersection of perpendicular tangents to the ellipse $\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{b}^{2}}}=1$ , is

Question

Accepted Answer

${{x}^{2}}+{{y}^{2}}={{a}^{2}}+{{b}^{2}}$

Answer

${{x}^{2}}+{{y}^{2}}={{a}^{2}}-{{b}^{2}}$

Answer

${{x}^{2}}-{{y}^{2}}={{a}^{2}}-{{b}^{2}}$

Answer

${{x}^{2}}-{{y}^{2}}={{a}^{2}}+{{b}^{2}}$

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