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Question: The value of k so that ${{x}^{2}}+{{y}^{2}}+kx+4y+2=0$ and $2({{x}^{2}}+{{y}^{2}})-4x-3y+k=0$ cut orthogonally is



1) $\frac{10}{3}$
2) $\frac{-8}{3}$
3) $\frac{-10}{3}$
4) $\frac{8}{3}$
Solution: Explanation: No Explanation
System of circles

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