circle

Question: If the straight line $y=mx+c$ touches the circle ${{x}^{2}}+{{y}^{2}}-4y=0$ , then the value of c will be

1) $1+\sqrt{1+{{m}^{2}}}$

2) $1-\sqrt{{{m}^{2}}+1}$

3) $2(1+\sqrt{1+{{m}^{2}}})$

4) $2+\sqrt{1+{{m}^{2}}}$

Solution:

Explanation: No Explanation

Tangent and normal to a circle

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