Categories > circle > Tangent and normal to a circle > Given the circles ${{x}^{2}}+{{y}^{2}}-4x-5=0$ and ${{x}^{2}}+{{y}^{2}}+6x-2y+6=0$ . Let P be a point $(\alpha ,\beta )$ such that the tangents from P to both the circles are equal, then

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Question: Given the circles ${{x}^{2}}+{{y}^{2}}-4x-5=0$ and ${{x}^{2}}+{{y}^{2}}+6x-2y+6=0$ . Let P be a point $(\alpha ,\beta )$ such that the tangents from P to both the circles are equal, then


1) $2\alpha +10\beta +11=0$
2) $2\alpha -10\beta +11=0$
3) $10\alpha -2\beta +11=0$
4) $10\alpha +2\beta +11=0$
Solution: Explanation: No Explanation
Tangent and normal to a circle

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