circle

Question: The equation of the circle which passes through the point of intersection of circles ${{x}^{2}}+{{y}^{2}}-8x-2y+7=0$ and ${{x}^{2}}+{{y}^{2}}-4x+10y+8=0$ and having its centre on$y$ -axis, will be



1) ${{x}^{2}}+{{y}^{2}}+22x+9=0$
2) ${{x}^{2}}+{{y}^{2}}+22x-9=0$
3) ${{x}^{2}}+{{y}^{2}}+22y+9=0$
4) ${{x}^{2}}+{{y}^{2}}+22y-9=0$
Solution: Explanation: No Explanation
System of circles

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