circle

Question: The point of contact of the tangent to the circle ${{x}^{2}}+{{y}^{2}}=5$ at the point (1, –2) which touches the circle ${{x}^{2}}+{{y}^{2}}-8x+6y+20=0$ , is



1) (2, –1)
2) (3, –1)
3) (4, –1)
4) (5, –1)
Solution: Explanation: No Explanation
Tangent and normal to a circle

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